Integration Problem 3

April 8, 2021 By Xander Integrals

Integral taken from instagram user @integralsforyou

Python \int\frac{e^{\frac{1}{x}}}{x^2}dx 1 \int\frac{e^{\frac{1}{x}}}{x^2}dx

Python =\int e^{(x^{-1})}\cdot x^{-2}dx 1 =\int e^{(x^{-1})}\cdot x^{-2}dx

let $u=x^{-1}$

Python du=-x^{-2} 1 du=-x^{-2}

Python =-\int e^udu 1 =-\int e^udu

Python =-e^u+C 1 = - e^u + C

Python =-e^{\frac{1}{x}}+C 1 =-e^{\frac{1}{x}}+C