Integral taken from instagram user @integralsforyou
$$\int\frac{e^{\frac{1}{x}}}{x^2}dx$$
$$=\int e^{(x^{-1})}\cdot x^{-2}dx$$
let $u=x^{-1}$
$du=-x^{-2}$
$$=-\int e^udu$$
$$=-e^u+C$$
$$=-e^{\frac{1}{x}}+C$$
Integral taken from instagram user @integralsforyou
$$\int\frac{e^{\frac{1}{x}}}{x^2}dx$$
$$=\int e^{(x^{-1})}\cdot x^{-2}dx$$
let $u=x^{-1}$
$du=-x^{-2}$
$$=-\int e^udu$$
$$=-e^u+C$$
$$=-e^{\frac{1}{x}}+C$$