#### Integration Problem 3

Integral taken from instagram user @integralsforyou

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\int\frac{e^{\frac{1}{x}}}{x^2}dx |

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=\int e^{(x^{-1})}\cdot x^{-2}dx |

let u=x^{-1}

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du=-x^{-2} |

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=-\int e^udu |

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=-e^u+C |

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=-e^{\frac{1}{x}}+C |